-20p^2-46p-24=0

Solution for -20p^2-46p-24=0 equation:

-20p^2-46p-24=0

a = -20; b = -46; c = -24;
Δ = b2-4ac
Δ = -462-4·(-20)·(-24)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-14}{2*-20}=\frac{32}{-40}
=-4/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+14}{2*-20}=\frac{60}{-40}
=-1+1/2
$